SPC CAT-1: Mock 3 (Functions & Pointers)

SPC CAT-1: Mock 3 (Functions & Pointers)

Pattern: 5 coding questions (2 Easy + 2 Medium + 1 Hard) covering user-defined functions, pointer swapping, abs/labs, difftime, and result calculations.
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Easy 1 — Maximum Using a Function

Write:

int max2(int a, int b)

and use it to print the larger number.

Input

17 9

Output

17

Another Input

0 0

Output

0

Another Input

-5 -10

Output

-5

Another Input

10 -10

Output

10

Another Input

100 100

Output

100

This covers:

• function declaration
• parameters
• return value
• function call
• modular programming

#include <stdio.h>

int max2(int a, int b)
{
    return a > b ? a : b;
}

int main()
{
    int a, b;

    scanf("%d %d", &a, &b);

    printf("%d\n", max2(a, b));

    return 0;
}

Easy 2 — Absolute Difference Using stdlib.h

Read two integers and print:

|a - b|

using:

abs()

Input

3 10

Output

7

Include:

#include <stdlib.h>

Another Input

0 0

Output

0

Another Input

-50 50

Output

100

Another Input

100 -50

Output

150

Another Input

10 10

Output

0

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a, b;

    scanf("%d %d", &a, &b);

    printf("%d\n", abs(a - b));

    return 0;
}

Medium 1 — Pointer Function Swap

Write:

void swap(int *a, int *b)

Swap two integers using pointers.

Input

12 35

Output

35 12

Another Input

0 0

Output

0 0

Another Input

-10 20

Output

20 -10

Another Input

100 -100

Output

-100 100

This covers:

int *p
&x
*p

plus functions.

#include <stdio.h>

void swap(int *a, int *b)
{
    int temp = *a;
    *a = *b;
    *b = temp;
}

int main()
{
    int a, b;

    scanf("%d %d", &a, &b);

    swap(&a, &b);

    printf("%d %d\n", a, b);

    return 0;
}

Medium 2 — Time Difference

Given two timestamps in seconds:

t1 t2

store them as time_t, use:

difftime()

and convert the elapsed time into:

hours minutes seconds

Input

0 3723

Output

1 2 3

Include:

#include <time.h>

Another Input

0 0 0 0 0 0

Output

0 0 0

Another Input

23 59 59 23 59 59

Output

0 0 36

Another Input

10 15 30 14 20 45

Output

0 0 5

#include <stdio.h>
#include <time.h>

int main()
{
    long long input1, input2;
    time_t t1, t2;
    int total_seconds;
    int hours, minutes, seconds;

    scanf("%lld %lld", &input1, &input2);

    t1 = (time_t)input1;
    t2 = (time_t)input2;

    total_seconds = (int)difftime(t2, t1);

    hours = total_seconds / 3600;
    total_seconds %= 3600;

    minutes = total_seconds / 60;
    seconds = total_seconds % 60;

    printf("%d %d %d\n",
           hours,
           minutes,
           seconds);

    return 0;
}

Hard 1 — Complete Student Result System

Input:

student_id
marks_obtained
total_marks
attendance
assignments

Calculate percentage accurately.

Grade:

>= 90 → A
>= 75 → B
>= 60 → C
>= 40 → D
else   → F

Eligibility:

percentage >= 60
attendance >= 75
assignments >= 5

Print:

ID: ...
Percentage: ...
Grade: ...
Eligibility: ...

Input

101 47 60 82 6

Output

ID: 101
Percentage: 78.33
Grade: B
Eligibility: Eligible

Another Input

1 2 3 80 5

Output

ID: 1
Percentage: 66.67
Grade: C
Eligibility: Eligible

Another Input

40 40 40 90 6

Output

ID: 40
Percentage: 100.00
Grade: A
Eligibility: Eligible

Another Input

39 50 60 85 8

Output

ID: 39
Percentage: 83.33
Grade: B
Eligibility: Eligible

Another Input

50 60 70 80 7

Output

ID: 50
Percentage: 85.71
Grade: B
Eligibility: Eligible

Another Input

80 80 80 95 10

Output

ID: 80
Percentage: 100.00
Grade: A
Eligibility: Eligible

Another Input

45 45 45 78 5

Output

ID: 45
Percentage: 100.00
Grade: A
Eligibility: Eligible

Another Input

100 100 100 100 10

Output

ID: 100
Percentage: 100.00
Grade: A
Eligibility: Eligible

Use:

• correct scanf
• type casting
• floating-point calculation
• relational operators
• &&
• nested ternary
• formatted output

#include <stdio.h>

int main()
{
    int student_id;
    int marks_obtained;
    int total_marks;
    int attendance;
    int assignments;

    float percentage;
    char grade;
    const char *eligibility;

    scanf("%d %d %d %d %d",
          &student_id,
          &marks_obtained,
          &total_marks,
          &attendance,
          &assignments);

    percentage =
        (float)marks_obtained /
        total_marks *
        100.0;

    grade =
        percentage >= 90.0 ? 'A' :
        percentage >= 75.0 ? 'B' :
        percentage >= 60.0 ? 'C' :
        percentage >= 40.0 ? 'D' :
                              'F';

    eligibility =
        (percentage >= 60.0 &&
         attendance >= 75 &&
         assignments >= 5)
        ? "Eligible"
        : "Not Eligible";

    printf("ID: %d\n", student_id);
    printf("Percentage: %.2f\n", percentage);
    printf("Grade: %c\n", grade);
    printf("Eligibility: %s\n", eligibility);

    return 0;
}